If you know the special angles then you should be able to calculate $\displaystyle \arctan(\sqrt{3})$.
What do you think about the first one? (look at the hint I gave you)
Arctan is the inverse of tan, so I guess if arctan= √(3) the. Tan = 1/√(3)? But yoi can't have √(3) Asa denominator, so do you multiply to make it √(3)/3?
Then again that could be completely wrong.
Arctan is the inverse of tan, so I guess if arctan= √(3) the. Tan = 1/√(3)? But yoi can't have √(3) Asa denominator, so do you multiply to make it √(3)/3? Then again that could be completely wrong.
it is. ... an inverse is not a reciprocal.
since $\displaystyle \tan\left(\frac{\pi}{3}\right) = \sqrt{3}$ , then $\displaystyle \arctan(\sqrt{3}) = \frac{\pi}{3}$