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Math Help - Inverse of Trig functions

  1. #1
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    Inverse of Trig functions

    Write the expression and evaluate. There is only one answer whIch should match the range of the inverse trig function.

    Sec^-1(-2)
    Tan^-1(sqrt3)

    Don't really know where to start with these two questions.
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  2. #2
    MHF Contributor Siron's Avatar
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    Re: Inverse of Trig functions

    You have to know some special angles, if not use your calculator.
    But you have to know -1\leq \cos(x) \leq 1.
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  3. #3
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    Re: Inverse of Trig functions

    I know the angles to the unit circle and all, but this is supposed to be a non-calculator problem.
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  4. #4
    MHF Contributor Siron's Avatar
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    Re: Inverse of Trig functions

    If you know the special angles then you should be able to calculate \arctan(\sqrt{3}).
    What do you think about the first one? (look at the hint I gave you)
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    Re: Inverse of Trig functions

    Arctan is the inverse of tan, so I guess if arctan= √(3) the. Tan = 1/√(3)? But yoi can't have √(3) Asa denominator, so do you multiply to make it √(3)/3?
    Then again that could be completely wrong.
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  6. #6
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    Re: Inverse of Trig functions

    Quote Originally Posted by crazycarlos61 View Post
    Arctan is the inverse of tan, so I guess if arctan= √(3) the. Tan = 1/√(3)? But yoi can't have √(3) Asa denominator, so do you multiply to make it √(3)/3?
    Then again that could be completely wrong.
    it is. ... an inverse is not a reciprocal.

    since \tan\left(\frac{\pi}{3}\right) = \sqrt{3} , then \arctan(\sqrt{3}) = \frac{\pi}{3}

    you need to review what an inverse function does.
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  7. #7
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    Re: Inverse of Trig functions

    Ah, thank you for telling me the definition.
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