# Math Help - Which Trigonemetric Identity do I need to use?

1. ## Which Trigonemetric Identity do I need to use?

Hi all,

I'm stuck with just one step now of a long problem.

Basically, how do I get from

$(1+2sinx)(\frac{1}{2}-sinx)$

to

$2cos(x)^{2}-\frac{3}{2}$

I've been told I need to use just one trigonometric identity, but I honestly can't think of any that will do it?

Many thanks.

2. ## Re: Which Trigonemetric Identity do I need to use?

Expand:
$(1+2\sin(x))\cdot \left(\frac{1}{2}-\sin(x)\right)$

Afterwards use the fact $\sin^2(x)=1-\cos^2(x)$

3. ## Re: Which Trigonemetric Identity do I need to use?

Thanks but now theirs just one part I can't get after expanding,

how to get from

$(2sinx)(-sinx)$

to

$2cos(x)^{2}-2$

this is the only missing step now,

many thanks again.

4. ## Re: Which Trigonemetric Identity do I need to use?

If you expand:
$(1+2\sin(x))\cdot \left(\frac{1}{2}-\sin(x)\right)$ then you get:
$\frac{1}{2}+\sin(x)-\sin(x)-2\sin^2(x)=\frac{1}{2}-2\sin^2(x)$

Use $\sin^2(x)=1-\cos^2(x)$ so you get:
$=\frac{1}{2}-2(1-\cos^2(x))$
$=...$

5. ## Re: Which Trigonemetric Identity do I need to use?

Thank you so much,

I really appreciate it.

6. ## Re: Which Trigonemetric Identity do I need to use?

Originally Posted by Srengam
$(1+2sinx)(\frac{1}{2}-sinx)$
to
$2cos(x)^{2}-\frac{3}{2}$
$(1+2sinx)(\frac{1}{2}-sinx)=\frac{1}{2}-2\sin^2(x)$

7. ## Re: Which Trigonemetric Identity do I need to use?

Originally Posted by Srengam
Thank you so much,

I really appreciate it.
You're welcome!