sec (-1/2) in radians?

**Fenixx09** · August 26th 2011, 02:00 PM

I have $cos^{-1}(\frac{-1}{2})$

I assume this is the same as $sec(\frac{-1}{2})$

How do I get the "exact value" in radians?

**skeeter** · August 26th 2011, 02:11 PM

Originally Posted by Fenixx09

I have $cos^{-1}(\frac{-1}{2})$

I assume this is the same as $sec(\frac{-1}{2})$

How do I get the "exact value" in radians?

$f(x) = \cos^{-1}(x)$ is the inverse trig function for cosine, not the reciprocal function.

the function's output is an angle.

$\cos^{-1}\left(-\frac{1}{2}\right) = \arccos\left(-\frac{1}{2}\right) = \frac{2\pi}{3}$

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