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Math Help - sec (-1/2) in radians?

  1. #1
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    sec (-1/2) in radians?

    I have cos^{-1}(\frac{-1}{2})

    I assume this is the same as sec(\frac{-1}{2})

    How do I get the "exact value" in radians?
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  2. #2
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    Re: sec (-1/2) in radians?

    Quote Originally Posted by Fenixx09 View Post
    I have cos^{-1}(\frac{-1}{2})

    I assume this is the same as sec(\frac{-1}{2})

    How do I get the "exact value" in radians?
    f(x) = \cos^{-1}(x) is the inverse trig function for cosine, not the reciprocal function.

    the function's output is an angle.

    \cos^{-1}\left(-\frac{1}{2}\right) = \arccos\left(-\frac{1}{2}\right) = \frac{2\pi}{3}
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