I have $\displaystyle cos^{-1}(\frac{-1}{2})$

I assume this is the same as $\displaystyle sec(\frac{-1}{2})$

How do I get the "exact value" in radians?

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- Aug 26th 2011, 02:00 PMFenixx09sec (-1/2) in radians?
I have $\displaystyle cos^{-1}(\frac{-1}{2})$

I assume this is the same as $\displaystyle sec(\frac{-1}{2})$

How do I get the "exact value" in radians? - Aug 26th 2011, 02:11 PMskeeterRe: sec (-1/2) in radians?