Can you solve each of those two equations now?
anyone has an idea on how to solve for this equation, (tan x)^2 = sin 2x
I know that sin 2x = 2sin xcos x and tan x = sin x/cos x, how ever i am having trouble simplifyng the equation into a single function so that I can solve for x.
thanks in advance
@sammys thanks for your advice on the other thread.
I arrived at the fourth line of the solution you had presented, and i never thought of factoring out sin x, i missed that part. yes, I can solve the remaining equations now. a million thanks to you.
to otherw whoe replied, thank you.
sin(x)/cos(x) = tan(x).
Multiply by sec^2(x), and change sec^2(x) to 1 + tan^2(x).
You then have a cubic equation in tan(x). Let u = tan(x), & factor to solve for u.