How do the quadrants affect my answer here?

I am told that$\displaystyle x= -7/25$ and $\displaystyle y = 15/8$, where x is in the second quandrant and y is in the third quandrant.

I need to find the exact value of:

$\displaystyle sin(x-y)$

I know I need to use the difference formula some how and I realise that sin is negative in the 3rd and 4th quadrant; however, I didn't know how to apply the negative sign for $\displaystyle y$. Do I apply it within the sin function or does it make the entire sin function negative? The confusion was because there are two values in different quadrants.

Also, how would I go about converting x and y into values that I can derive exact values from? Do I need to rearrange them before I apply the sum/difference formula or after?

Thanks.

Re: How do the quadrants affect my answer here?

Can't you just substitute $\displaystyle \displaystyle x$ and $\displaystyle \displaystyle y$ as given?

$\displaystyle \displaystyle \begin{align*} \sin{(x - y)} &= \sin{\left(-\frac{7}{25} - \frac{15}{8}\right)} \\ &= \sin{\left(-\frac{56}{200} - \frac{105}{200}\right)} \\ &= \sin{\left(-\frac{161}{200}\right)} \\ &= -\sin{\left(\frac{161}{200}\right)}\end{align*}$

This is as exact as you're going to get...

Re: How do the quadrants affect my answer here?

How did knowing the quadrants play any role at all then? I just figured that the statement was made for a reason. Also, I just assumed exact meant using the values for 30, 45, 60 as it also said without using a calculator.

PS. should be $\displaystyle -sin(431/200)$ right?

Re: How do the quadrants affect my answer here?

I suspect you have written the problem wrong- that the fractions are NOT x and y but are either sine or cosine of x and y. Otherwise, it makes no sense to say that a single number is in any specific quadrant.

Re: How do the quadrants affect my answer here?

Quote:

Originally Posted by

**terrorsquid** How did knowing the quadrants play any role at all then? I just figured that the statement was made for a reason. Also, I just assumed exact meant using the values for 30, 45, 60 as it also said without using a calculator.

PS. should be $\displaystyle -sin(431/200)$ right?

Yes it should be, I added the fractions wrong ><

Re: How do the quadrants affect my answer here?

Quote:

Originally Posted by

**HallsofIvy** I suspect you have written the problem wrong- that the fractions are NOT x and y but are either sine or cosine of x and y. Otherwise, it makes no sense to say that a single number is in any specific quadrant.

Ah yes sorry I read it a little fast :S

It should be:

$\displaystyle cos(x) = -7/25$ and $\displaystyle tan(y) = 15/8$

Durrrrr, my bad.

So would I draw two triangles using cosx and tany and then use the difference formula and substitute in the values from the traingles?

And would I apply the necessary sign to cos(x) and tan(y) now? ie -17/25 becomes -- = +17/25 and 15/8 stays +?

Working on it now will see what I get...

Re: How do the quadrants affect my answer here?

So I drew two triangles. $\displaystyle \bigtriangleup x = 7, 24, 25$ and $\displaystyle \bigtriangleup y = 8, 15, 17$.

Using the difference formula:

$\displaystyle sin(x-y) = sin(x)cos(y) - cos(x)sin(y)$

$\displaystyle = \frac{24}{25} * \frac{8}{17} - \frac{7}{25} * \frac{15}{17}$

$\displaystyle =\frac{87}{425}$

That's assuming the $\displaystyle -\frac{7}{25}$ became positive.

Re: How do the quadrants affect my answer here?

Or do I apply the quadrant sign when deriving values from the $\displaystyle sin(x)cos(y) - cos(x)sin(y) $ equation? i.e.:

$\displaystyle (\frac{24}{25})(-\frac{8}{17}) - (-\frac{7}{25})(-\frac{15}{17})$

$\displaystyle = -\frac{297}{425}$

Re: How do the quadrants affect my answer here?

Quote:

Originally Posted by

**terrorsquid** Or do I apply the quadrant sign when deriving values from the $\displaystyle sin(x)cos(y) - cos(x)sin(y) $equation? i.e.:

$\displaystyle (\frac{24}{25})(-\frac{8}{17}) - (-\frac{7}{25})(-\frac{15}{17})$

$\displaystyle = -\frac{297}{425}$

You need to keep the numbers the way they have been given.

Re: How do the quadrants affect my answer here?

Quote:

Originally Posted by

**Prove It** You need to keep the numbers the way they have been given.

So, to be clear, at what point do I use the information about which quadrant x and y are in?

Re: How do the quadrants affect my answer here?

Quote:

Originally Posted by

**terrorsquid** So, to be clear, at what point do I use the information about which quadrant x and y are in?

You don't need to worry about it at all in this case. It's not asking you to find any angles, it's asking you to find the sine of a difference of angles using the information given.

Re: How do the quadrants affect my answer here?

Ok,fair enough. It seems strange to include the information about the quadrants in the question if they aren't going to be used though doesn't it? Maybe trying to through me off :D

Re: How do the quadrants affect my answer here?

Because $\displaystyle cos(x) = -\frac{7}{25}$ and $\displaystyle x$ is in the 2nd quadrant, where sin(x) is positive, that would mean the 7 is negative and the 25 is positive right? So when substituting values into the sum formula equation I should be using a -7 shouldn't I?

Sorry if I am talking nonsense; can't seem to get it out of my head.

Re: How do the quadrants affect my answer here?

Quote:

Originally Posted by

**terrorsquid** Because $\displaystyle cos(x) = -\frac{7}{25}$ and $\displaystyle x$ is in the 2nd quadrant, where sin(x) is positive, that would mean the 7 is negative and the 25 is positive right? So when substituting values into the sum formula equation I should be using a -7 shouldn't I?

Because $\displaystyle x\in II~\&~y\in III$ we have:

$\displaystyle \sin(x)=\frac{24}{25},~\sin(y)=\frac{-15}{17},~\&~\cos(y)=\frac{-8}{17}$

Does that help?

Re: How do the quadrants affect my answer here?

Quote:

Originally Posted by

**Plato** Because $\displaystyle x\in II~\&~y\in III$ we have:

$\displaystyle \sin(x)=\frac{24}{25},~\sin(y)=\frac{-15}{17},~\&~\cos(y)=\frac{-8}{17}$

Does that help?

Yes, thanks.

So for $\displaystyle sin(x)cos(y) - cos(x)sin(y)$ I would have:

$\displaystyle \left(\frac{24}{25}\right)\left(\frac{-8}{17}\right) - \left(\frac{-7}{25}\right)\left(\frac{-15}{17}\right)$

$\displaystyle = -\frac{297}{425}~~?$

Just out of curiosity, in $\displaystyle \bigtriangleup y$ where $\displaystyle y\in III$ you have made the two edges (15 & 8) negative and the hypotenuse (17) positive which makes tan positive and both sin & cos negative, which is correct for $\displaystyle III$. Does it matter that you do it this way? for example, if you were to make the hypotenuse negative and the two edges positive, you would still have tan +, sin -, cos -.

Thanks.