I think it's very good document .
(Do you have more documents for other subjects maybe?)
I have attached a pdf document containing the vast majority of trigonometry I have needed to know on a working basis. The first page consists of trigonometry I think everyone should have memorized. I have never needed to have anything more than the first sheet memorized for any application. The second page is a non-exhaustive sheet of most of the trigonometric identities that I have found useful, and a few more besides.
It is my opinion that a student who memorizes the first sheet, and can derive anything on the second sheet, has a fairly good grasp of trigonometry.
I hope this proves useful.
I don't really have any others like this one. The reason is the only courses I have taught were Calculus, and this was intended as a review sheet for incoming freshman who were taking my class. I do have problem-solving stickies in the Other Topics and Advanced Applied Math forums. That's about it. Chris L T521 has a very good DE's tutorial, and there's already a LaTeX tutorial and a Calculus tutorial. There's even something in the pre-algebra and algebra forum as well as the linear and abstract algebra forum. So that's most of the forums that I pay the most attention to that even admit of such a document.
I find this enormously useful (and encouraging! as I can see how far I've come in a relatively short period of time; and salutary! as I can see how far I have to go before my exam on 17th July)
thanks Ackbeet: thoughtful and very useful!
is there anybody can help me to solve this problem
Substense bar method:
A traverse line AB is being measured by theodolite and substense bar. At atation A, the horizontal axis of the theoadolite is 1.48m above the ground mark and the horizontal angle substense by 2-mete substense bat set up at station B is 41'18". The substense bar is 1.22m above the ground mark and the vertical angle measured to it on the theodolite is 13deg56minutes. Determine the two ground station marks.
actually i got this problem in my textbook but it is too broad solution:
HD=1/tan(teta/2) HD=1/tan(42'18"/2) = 162.54 m
is there anybody can till me how he got the answer 162.54 m
or how he simplify the formula please help!