If I have , then I have
well, tan is equal to 1 in . It's equal to -1 in quadrant 2 and 4.
So where n is all reals.
but why isn't it also , since tan is negative in the 4th quadrant as well?
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Actually it's , and the tangent function is positive in the first and third quadrants. where .
Sorry it my quickness to get the latex correct I wrote the problem out wrong. its supposed to have been TanX+1, not tanx-1
Well to answer your question, both answers are correct. They can be written in a more compact way as where . The period of the tangent function is , not .
Originally Posted by DamenFaltor Sorry it my quickness to get the latex correct I wrote the problem out wrong. its supposed to have been TanX+1, not tanx-1 I suppose you still have the same difficulty as before:
The tangent function is periodic with a period of π not 2π.
Ah yes, I forgot about the periodicity of Tan being different.
ok so to provide:
Would be a correct answer?
The second of those is redundant, since .