Originally Posted by
OhCurtis Solve for 0 <x< 360 degrees
Okay this is probably a stupid question but I'm really not doing so good with this unit so far.
Apparently to get the answer you have to take a squaring approach
sinx=-cosx
Square both sides
sin^2x=cox^2x
sin^2x=1-sin^2x
2sin^2x=1
sin^2x=1/2
sinx=+ or - (1/sqrt(2))
45, 135, 225, 315 degrees
BUT what I would have done is
sinx=-cosx
-sinx/cosx=cosx/cosx
-tanx=1
tanx=-1
135, 315 degrees
I need someone to tell me why my thinking process would or would not work. Thanks!
EDIT: Similar question I need help with too
sinx-cosx=1
Here's my approach
(sinx)^2=(1+cosx)^2
sin^2x=1+2cosx+cos^2x
1-cos^2x=1+2cosx+cos^2x
0=2cosx+2cos^2x
0=2cosx(1+cosx)
cosx=0,-1
90, 180, 270 degrees
However 270 is not an answer
I feel like I understand the concept just not getting the same answers. Any help would be GREATLY appreciated