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Math Help - problem involving triangle and profit

  1. #1
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    problem involving triangle and profit

    The question reads:

    Due to previous tunneling experience, the firm estimates a cost of $18,000 per meter for boring through this type of rock and constructing the tunnel according to required specifications. If management insists on a 30% profit, what will be their minimum bid to the nearest thousand.

    The sides are 1200m, 1600m, 330.3m
    Attached is the picture of the triangle that I worked out.

    http://i56.tinypic.com/m93ltg.jpg

    If someone can explain how to continue on from here that would be fantastic.

    I had to use the cosine law to get the 330.3m, so I thought it would be relevant to post here.

    -- Thanks
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  2. #2
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    e^(i*pi)'s Avatar
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    Re: problem involving triangle and profit

    How did you get 330.3m? I used the cosine law to get 1175.2m for the "missing" side.

    c^2 = a^2+b^2 - 2ab\cos(C)

    With your numbers:

    c = \sqrt{1600^2 + 1200^2 - 2 \cdot 1600 \cdot 1200 \cos(47^o)} \approx 1175.2\ m
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  3. #3
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    Re: problem involving triangle and profit

    Good catch, I didn't enter the numbers in proper order and got the wrong answer. When I put them in all at the same time it came out to be 1175.2

    So, continuing on with the triangle and the 30% profit, any tips?
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  4. #4
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    e^(i*pi)'s Avatar
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    Re: problem involving triangle and profit

    You have the cost per metre and the amount of metres.

    To get a 30% profit on that you multiply the actual cost by 1.3
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    Re: problem involving triangle and profit

    Thanks for your help. Much appreciated.
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