Prove that in any triangle we have the following relation

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- July 18th 2011, 11:41 AMTheodorMunteanuRelation between cosines and lenghts of triangle
Prove that in any triangle we have the following relation

- July 18th 2011, 11:46 AMSironRe: Relation between cosines and lenghts of triangle
What's ? ...

It can be useful to know that in a triangle:

A+B+C=180° - July 18th 2011, 11:47 AMTheodorMunteanuRe: Relation between cosines and lenghts of triangle
R is radius of the circumscribed circle.

- July 18th 2011, 12:17 PMwaqarhaiderRe: Relation between cosines and lenghts of triangle
RHS = 8cos(A/2) cos(B/2) cos(C/2) = 8 sqrt {[s^3(s-a)(s-b)(s-c)]/(abc)^2 }

= 8s(area of triangle)/abc

now using s = (a+b+c)/2 and 4(area of triangle)/abc = 1/R you get required result - July 18th 2011, 12:23 PMTheodorMunteanuRe: Relation between cosines and lenghts of triangle
could you be more speciffic?

- July 18th 2011, 12:36 PMwaqarhaiderRe: Relation between cosines and lenghts of triangle
about what, if you point out the problem

- July 18th 2011, 12:53 PMTheodorMunteanuRe: Relation between cosines and lenghts of triangle
- July 19th 2011, 11:12 AMwaqarhaiderRe: Relation between cosines and lenghts of triangle
cos(A/2) = sqrt[ s(s-a)/bc] , cos(B/2) = sqrt[ s(s-b)/ac] and cos(C/2) = sqrt[s(s-c)/ab]