The trig identity approach is confusing you. And please refer again to ThePerfectHacker's post: it is not . This is not an identity! The identity he used is .
Let's try it this way: <-- Factor the common
Now either
or
-Dan
Last edited by topsquark; Sep 4th 2007 at 11:33 AM.
The trig identity approach is confusing you. And please refer again to ThePerfectHacker's post: it is not . This is not an identity! The identity he used is .
Let's try it this way: <-- Factor the common
Now either
or
-Dan
im still not quite getting it, ur saying cos(2x) but i dotn have cos(2x) in my expression? ummmm sorry
you lost me by the factoring?
You do realise Topsquark that I have printed that one out and framed it against my wall...
Well because it was you that corrected me I seriously thought about coming up with a really complicated argument involving Green's functions and doing a lot of chest thumping, but I decided not to.