Find the exact values of x between 0 and 360 for

2 cos^3(x) - cos(x) = 0

-----------------------------------

So what i did was cos(x) = x

therefore 2x^3 - x = 0

Now i got stuck there??

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- September 4th 2007, 02:14 AMtaurusSolve for value
Find the exact values of x between 0 and 360 for

2 cos^3(x) - cos(x) = 0

-----------------------------------

So what i did was cos(x) = x

therefore 2x^3 - x = 0

Now i got stuck there?? - September 4th 2007, 03:51 AMThePerfectHacker
- September 4th 2007, 04:39 AMtaurus?
- September 4th 2007, 04:47 AMtopsquark
- September 4th 2007, 05:07 AMtaurus
- September 4th 2007, 06:50 AMjanvdl

Set

Now set like it was

But we know that from our identities

So then

For

For

- September 4th 2007, 07:14 AMtaurusthanks
ok right, so u jus solve for each of those cos

- September 4th 2007, 07:16 AMjanvdl
- September 4th 2007, 07:18 AMtaurus
wait ur answers r different to that other guys?

- September 4th 2007, 07:21 AMjanvdl
- September 4th 2007, 11:34 AMtopsquark
- September 5th 2007, 03:06 AMjanvdl
- September 5th 2007, 05:31 AMtopsquark