# Evaluate 4[sin4 30+cos4 60]-2/3[sin2 60-cos2 45 ] + 1/2 tan2 60

• Jul 15th 2011, 09:37 PM
butler12
Evaluate 4[sin4 30+cos4 60]-2/3[sin2 60-cos2 45 ] + 1/2 tan2 60
4[sin4 30+cos4 60]-2/3[sin2 60-cos2 45 ] + 1/2 tan2 60
• Jul 15th 2011, 10:19 PM
icedtrees
Re: can you help me with this trignometery question
To do this question exact values must be known, that is:

$sin(30) = cos(60) = \frac{1}{2}$
$tan(60) = \sqrt(3)$
$sin(45) = cos(45) = \frac{1}{\sqrt(2)}$

If you did not already know:

$tan(30) = \frac{1}{\sqrt(3)}$
$sin(60) = cos(30) = \frac{\sqrt(3)}{2}$
$tan(45) = 1$

Now, all that is needed is a substitution:

$4(\frac{1}{2})^4 + 4(\frac{1}{2})^4 - \frac{2}{3}[(\frac{1}{2})^2 - (\frac{1}{\sqrt(2)})^2] + \frac{1}{2}[\sqrt(3)]^2$

and then it should be easy to solve from there
• Jul 15th 2011, 11:03 PM
butler12
Re: can you help me with this trignometery question
hi thanks for this solutions, and do you have any ideas you can give me for solving my questions. because this is just a try i gave to this place for solutions. This question i had got from my institute pioneermathematics and they have solutions too.
• Jul 15th 2011, 11:36 PM
icedtrees
Re: can you help me with this trignometery question
I can't give you ideas for solving other questions if I don't know what the questions are. Are you asking for the final answer to the question? I evaluated it to be 11/6, but I'm sure you could have done it as well
• Jul 16th 2011, 02:31 PM
mr fantastic
Re: can you help me with this trignometery question
Quote:

Originally Posted by butler12
hi thanks for this solutions, and do you have any ideas you can give me for solving my questions. because this is just a try i gave to this place for solutions. This question i had got from my institute pioneermathematics and they have solutions too.

You were told exactly how to do the question!

It is insulting to post questions in order to 'test' us.