Hi Forum, Please do help me by solving below equation, kindly explain all steps Thanks in advance, if Sec$+tan$ = p, Show that P2 – 1 / P2 + 1 = Sin$
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Where did P2 come from and how is it related to p?
Originally Posted by mvijay Hi Forum, Please do help me by solving below equation, kindly explain all steps Thanks in advance, if Sec$+tan$ = p, Show that P2 – 1 / P2 + 1 = Sin$ Hi mvijay, $\displaystyle \sec x+\tan x=p$ $\displaystyle \frac{p^2-1}{p^2+1}=\frac{(\sec x-\tan x)^{2}}{(\sec x+\tan x)^{2}}$ Simplify the expression and use the trigonometric identity, $\displaystyle \sec^{2}x=1+\tan^{2}x$. I am sure you can do it form here.
Thanks a lot dear Sudharaka.........
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