Period of sums/multiplied sines/cosines
Hello
I am trying to revise some rules regarding the period of sines (or cosines) when (a) they are added , and (b) they are multiplied. I haven't had too much luck Googling this topic.
For example, what would be the fundamental period of:
y=cos(2.pi.2x) + cos(2.pi.3x)
Or, if we multiply:
y=cos(2.pi.2x).cos(2.pi.3x)
People have suggested to me that I use trig. identities (or complex exponentials) but I am sure there is a more intuitive way such as considering the phases between both parts.
Any ideas appreciated !
Cheers
Gabber
Re: Period of sums/multiplied sines/cosines
Re: Period of sums/multiplied sines/cosines
Thank you Kaylan
So it looks like the period will be the LCM (lowest common multiple) of the individual periods?
I think the answer to your question is SIX
Do you have any good ideas how to find the period when the cosines are multiplied?
Thanks again
Gabber
Re: Period of sums/multiplied sines/cosines
Quote:
So it looks like the period will be the LCM (lowest common multiple) of the individual periods?
I think the answer to your question is SIX
That's true period in the case of sums is the LCM of individual periods.
Quote:
Do you have any good ideas how to find the period when the cosines are multiplied?
Now in the case when cosines are multiplied or for that matter any powers of sines or cosines can be handled by transforming them to sums of sines and cosines.
Kalyan.
Re: Period of sums/multiplied sines/cosines
Here are few examples
as you can see since the LCM has already been obtained during the sum and difference of angles the approach does not change drastically. However in the following example the approach varies
,
.
Kalyan
Re: Period of sums/multiplied sines/cosines
your question is:
--------------------------
For example, what would be the fundamental period of:
y=cos(2.pi.2x) + cos(2.pi.3x)
Or, if we multiply:
y=cos(2.pi.2x).cos(2.pi.3x)
-----------------------------
my anwer is:
in both cases the total period is
x=(0;1)
that is the least common multiple of the two periods.
in fact the 1st period is x=(0;1/2)
and the 2nd period is x=(0;1/3)
therefore the range x=(0;1) is the least common multiple of the two single ranges.
bye-bye
mike999
Re: Period of sums/multiplied sines/cosines
Thanks everybody
Mike, you seem to be saying that this LCM method is also true for procucts of sines (or cosines), not just when they are added. So is this generally true?
Kalyan, in your cos-cubed example, after you transform it, we have periods of 1 and 4. So again it is the LCM.
Thanks again
Matt
Re: Period of sums/multiplied sines/cosines
Hi Matt,
Quote:
Mike, you seem to be saying that this LCM method is also true for procucts of sines (or cosines), not just when they are added. So is this generally true?
Kalyan, in your cos-cubed example, after you transform it, we have periods of 1 and 4. So again it is the LCM.
The idea of taking an LCM is valid for the case of sum or multiplication of functions. All I was suggestting is that you have to consider taking the transformations when multiplication of functions is involved as in the case of
are involved.
Kalyan.
Re: Period of sums/multiplied sines/cosines
Hello again
Thank you for all your help so far Kalyan
I am glad you agree about the LCM idea !
However, I have just been trying an online graphing program.
Firstly I tried cos(2pi*(x/2))*cos(2pi*(x/3)). As expected I can see that the pattern repeats every 6 units.
Then I tried cos(2pi*x)*cos(2pi*(x/3)). Maybe I am wrong, but it looks like a period of 1.5. There is ALSO a period of 3. But the lowest common multiple (LCM) idea does not suggest that !
Does this mean that perhaps the LCM idea is not the way to go and really we should always use trig identies to get the period when our sines or cosines are multiplied?
Re: Period of sums/multiplied sines/cosines
Re: Period of sums/multiplied sines/cosines
Another way to look at it is that you have taken the
i.e LCM of denominators and divided it by HCF of numerators )
T = 3/2.
Kalyan.
Re: Period of sums/multiplied sines/cosines
Sorry for the late reply. Apart from lots of work I have also been revising my trig identities. It was a long ago I learnt those. Thanks again for all of your help Kalyanram.