Verifying a trig identity.

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• June 21st 2011, 05:17 PM
NewMath
Verifying a trig identity.
cos^2 - sin^2 / cos^2 + sin * cos = 1-tan * 1-cos / cos
• June 21st 2011, 05:21 PM
pickslides
Re: This identity is really challenging...please help me
You're notation is very confusing, is this the identity?

$\displaystyle \frac{\cos^2x - \sin^2x}{\cos^2x + \sin x \cos x} = \frac{(1-\tan x)( 1-\cos x)}{ \cos x }$
• June 21st 2011, 05:30 PM
NewMath
Re: This identity is really challenging...please help me
Quote:

Originally Posted by pickslides
You're notation is very confusing, is this the identity?

$\displaystyle \frac{\cos^2x - \sin^2x}{\cos^2x + \sin x \cos x} = \frac{(1-\tan x)( 1-\cos x)}{ \cos x }$

yea the right side is right but on the left side, 1-tanx is isolated. Don't know if that matters but sorry i don't know how to use better notation
• June 21st 2011, 09:53 PM
mr fantastic
Re: This identity is really challenging...please help me
Quote:

Originally Posted by NewMath
yea the right side is right but on the left side, 1-tanx is isolated. Don't know if that matters but sorry i don't know how to use better notation

There is no 1 - tan(x) on the left hand side. How can we help you if you continually post incomplete, ambiguous and wrong information, even after being asked for clarification.

If you cannot post your questions accurately people are simply not going to waste their time playing guessing games as to what the question is.

Learn some simple latex if you want your mathematical expressions to be undertsood. There is an entire forum at MHF devoted to it.