Giving answers to the nearest degree, find in the interval 0<x<360
Giving answers to the nearest degree, find in the interval 0<x<360 all the solutions of:
10 sin(x+26) cos(x+26)=1
rather than the answer, id like to know the solution ie how to work it out.
i have my mock exam tomorrow, please answer me asap please.
thanks,
neilofbodom
Re: Giving answers to the nearest degree, find in the interval 0<x<360
Use the identity } \equiv 2\sin{(\theta)}\cos{(\theta)})
. If you let 
then
![\displaystyle 10\sin{(x + 26)}\cos{(x + 26)} \equiv 5\cdot 2\sin{(x + 26)}\cos{(x + 26)} \equiv 5 \sin{[2(x + 26)]}](http://latex.codecogs.com/png.latex?\displaystyle 10\sin{(x + 26)}\cos{(x + 26)} \equiv 5\cdot 2\sin{(x + 26)}\cos{(x + 26)} \equiv 5 \sin{[2(x + 26)]})
.
So now you need to solve ![\displaystyle 5\sin{[2(x + 26)]} = 1](http://latex.codecogs.com/png.latex?\displaystyle 5\sin{[2(x + 26)]} = 1)
.
Re: Giving answers to the nearest degree, find in the interval 0<x<360
oh ok. so then, ill find what x is and use the general solution of sin to find the other values, right?
Re: Giving answers to the nearest degree, find in the interval 0<x<360
Yes. Remember that the sine function is positive in the first and second quadrants.
Re: Giving answers to the nearest degree, find in the interval 0<x<360
