Stuck on this question, Thanks for your help.
Thanks both of you, but i am still having issues. I'm doing a practice provincial exam for Pmath 12 and I haven't done this stuff in half a year ( also the unit I struggled the most with).
Here are the possible answer's:
A- (pi)/6 and 7(pi)/6
B-5(pi)/6 and 11(pi/6
C- (pi)/6 and 7(pi)/6 and (pi)/2 and 3(pi)/2
D-5(pi)/6 and 11(pi/6 and (pi)/2 and 3(pi)/2
Thanks for any further help
$\displaystyle \begin{aligned} \sqrt{3}\cos{x}\tan{x}+\cos{x} & = \sqrt{3}\sin{x}+\cos{x} \\&= 2\bigg(\frac{\sqrt{3}}{2}\sin{x}+\frac{1}{2}\cos{x }\bigg) \\& = 2\bigg(\cos{\frac{\pi}{6}}~\sin{x}+\sin{\frac{\pi} {6}}\cos{x}\bigg) \\& = 2\sin\left(x+\frac{\pi}{6}\right).\end{aligned}$