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Math Help - Prove cot(a)+cot(b)+cot(c)=cot(a).cot(b).cot(c)

  1. #1
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    Prove cot(a)+cot(b)+cot(c)=cot(a).cot(b).cot(c)

    Given a,b,c are acute angles and a+b+c=90, prove that

    cot(a)+cot(b)+cot(c)=cot(a).cot(b).cot(c)

    Can anyone prove this? Thanks...
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  2. #2
    MHF Contributor FernandoRevilla's Avatar
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    Re: Prove cot(a)+cot(b)+cot(c)=cot(a).cot(b).cot(c)

    Hint: \cot (a+b)=\cot (90^{\circ}-c)=\tan c=\dfrac{1}{\cot c}\Rightarrow \ldots
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