Alternatively, you can find the exact value of by usual trigonometry.
Hello, BabyMilo!
Let
Let
From [1]: .
Hence, is in this right triangle.
Code:* 1 * * * * * α * * * * * * 2x
From [2]: .
Hence, is in this right triangle:
Code:* ** 1 * * * * 2x * * * β * * * * *
We see that the two triangles are congruent.
That is, and are in the same right triangle!
Code:* 1 * β* * * * α * * * * * * 2x
Therefore: .