Thread: Two angles and the angle in between in 180 degrees; maximization

Hi Forum!
I have a question



We are to find the x coordinate of P to maximize abp
a(1,2) [use your imagination here, the graph is not right hahaha]
b(-1,1)
c(-1,0)
d(1,0)

Now, if we consider t as the x coordinate of P, we have:
Tan(A)=2/1-t
Tan(B)=1/1+t

If we have to find Tan(C), how should we do it?
A+B+C=180
C=180-A-B
Where do we go from there?

We know that tan(180) is 0, but how are we going to use it?


Thanks.

Originally Posted by Zellator

Hi Forum!
I have a question



We are to find the x coordinate of P to maximize abp
a(1,2) [use your imagination here, the graph is not right hahaha]
b(-1,1)
c(-1,0)
d(1,0)

Now, if we consider t as the x coordinate of P, we have:
Tan(A)=2/1-t
Tan(B)=1/1+t

If we have to find Tan(C), how should we do it?
A+B+C=180
C=180-A-B
Where do we go from there?

We know that tan(180) is 0, but how are we going to use it?


Thanks.

, and so Now take it from there ... .

Originally Posted by Opalg

, and so Now take it from there ... .

Hey Opalg!
I remember seeing this formula somewhere, but I didn't know how to put in motion.
So, it was easier than I thought. Thanks for your explanation!!!
All the best!