Two angles and the angle in between in 180 degrees; maximization
Hi Forum!
I have a question
https://lh6.googleusercontent.com/-u...Q6Y/angles.jpg
We are to find the x coordinate of P to maximize abp
a(1,2) [use your imagination here, the graph is not right hahaha]
b(-1,1)
c(-1,0)
d(1,0)
Now, if we consider t as the x coordinate of P, we have:
Tan(A)=2/1-t
Tan(B)=1/1+t
If we have to find Tan(C), how should we do it?
A+B+C=180
C=180-A-B
Where do we go from there?
We know that tan(180) is 0, but how are we going to use it?
Thanks.
Re: Two angles and the angle in between in 180 degrees; maximization
Quote:
Originally Posted by
Zellator
Hi Forum!
I have a question
https://lh6.googleusercontent.com/-u...Q6Y/angles.jpg
We are to find the x coordinate of P to maximize abp
a(1,2) [use your imagination here, the graph is not right hahaha]
b(-1,1)
c(-1,0)
d(1,0)
Now, if we consider t as the x coordinate of P, we have:
Tan(A)=2/1-t
Tan(B)=1/1+t
If we have to find Tan(C), how should we do it?
A+B+C=180
C=180-A-B
Where do we go from there?
We know that tan(180) is 0, but how are we going to use it?
Thanks.
, and so
Now take it from there ... .
Re: Two angles and the angle in between in 180 degrees; maximization
Quote:
Originally Posted by
Opalg
 = -\tan C)
, and so
 = -\frac{\tan A + \tan B}{1-\tan A\tan B}.)
Now take it from there ... .
Hey Opalg!
I remember seeing this formula somewhere, but I didn't know how to put in motion.
So, it was easier than I thought. Thanks for your explanation!!!
All the best! :)