The graphs of f(x) = 2sin(x) - 1 (blue) , and g(x) = 3cos(x) + 2 (red)
are shown below:
What equation would have the intersection points of the graphs as its solutions?
I know that I need to set the equations equal to one another:
2sin(x) -1 = 3cos(x) + 2
2sin(x) -1 -2 = 3cos(x)
2sin(x) -3 = 3cos(x)
I think I need to get all of the trig functions in terms of the same ratio, but I'm not sure how to do that. Nor am I sure where to go from there.
Any help would be greatly appreciated. This is my last trig question and I'm finally done the unit!