1. ## Solving for theta

Hello,
I'm not sure how to solve this nor where to start...

question- solve for θ over the specified domain
tanθ= -1/sqr(3)
domain= -180 \leqslant θ \leqslant 180

If anyone can start me off or tell me what to do it'll be appreciated allot

thanks

2. Originally Posted by sassysue
Hello,
I'm not sure how to solve this nor where to start...

question- solve for θ over the specified domain
tanθ= -1/sqr(3)
domain= -180 \leqslant θ \leqslant 180

If anyone can start me off or tell me what to do it'll be appreciated allot

thanks
Is...

$\tan \theta= \frac{\sin \theta}{\sqrt{1-\sin^{2} \theta}}= - \frac{1}{\sqrt{3}}$ (1)

Set $\sin \theta = x$ and then solve for x...

Kind regards

$\chi$ $\sigma$

3. You should be familiar with similar triangles to be able to solve $\displaystyle \tan{\theta} = \frac{1}{\sqrt{3}}$ for $\displaystyle \theta$, and then evaluate the equivalent angles in the second and fourth quadrants (where the tangent function is negative).