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Thread: Solving for theta

  1. June 2nd 2011, 01:30 AM #1
    sassysue
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    Smile Solving for theta

    Hello,
    I'm not sure how to solve this nor where to start...

    question- solve for θ over the specified domain
    tanθ= -1/sqr(3)
    domain= -180 \leqslant θ \leqslant 180

    If anyone can start me off or tell me what to do it'll be appreciated allot

    thanks
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  2. June 2nd 2011, 02:32 AM #2
    chisigma
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    Quote Originally Posted by sassysue View Post
    Hello,
    I'm not sure how to solve this nor where to start...

    question- solve for θ over the specified domain
    tanθ= -1/sqr(3)
    domain= -180 \leqslant θ \leqslant 180

    If anyone can start me off or tell me what to do it'll be appreciated allot

    thanks
    Is...

    \tan \theta= \frac{\sin \theta}{\sqrt{1-\sin^{2} \theta}}= - \frac{1}{\sqrt{3}} (1)

    Set \sin \theta = x and then solve for x...

    Kind regards

    \chi \sigma
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  3. June 2nd 2011, 02:35 AM #3
    Prove It
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    You should be familiar with similar triangles to be able to solve \displaystyle \tan{\theta} = \frac{1}{\sqrt{3}} for \displaystyle \theta, and then evaluate the equivalent angles in the second and fourth quadrants (where the tangent function is negative).
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