i really need to know how to simplify this equation for -infinity<t<infinity,

cos(arctan(t))...

thanks

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- Aug 29th 2007, 09:20 PMmer1988simplifying inverse and normal trig functions
i really need to know how to simplify this equation for -infinity<t<infinity,

cos(arctan(t))...

thanks - Aug 29th 2007, 10:43 PMred_dog
Let

So we have to find , knowing .

We have

On the interval , , so we choose the sign

Thus,