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Math Help - Trigonometry word problem

  1. #1
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    Question Trigonometry word problem

    A hang glider is observed from a field due east at an angle of elevation of 50 degree. The hang glider is 2 km away from the observer at this first field. The angle of elevation from a second field is 23 degree. The second field is 3.5 km away from the first at a bearing of 155 degree. How high is the hang glider.

    This part is really confuses me----->The angle of elevation from a second field is 23 degree. The second field is 3.5 km away from the first at a bearing of 155 degree. How high is the hang glider.

    Please help. Thank you
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  2. #2
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    Do you know that "Angle of Elevation" is ALWAYS measured from the Horizontal?

    I'm a little puzzled by the "2 km away" hint. Is that horizontal distance or direct line of sight?
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  3. #3
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    Yes I know that angle of elevation is always measured from the horizontal but the second field has to angle such as 23angle and bearing 155 angle.

    The answer from my text book is 1.8km; I hope you can figure it out.Thank you.

    Quote Originally Posted by TKHunny View Post
    Do you know that "Angle of Elevation" is ALWAYS measured from the Horizontal?

    I'm a little puzzled by the "2 km away" hint. Is that horizontal distance or direct line of sight?
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  4. #4
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    Label glider shadow on the ground, with exactly overhead sun, Point G
    Orient your drawing for North.
    Move West and put the point in Field #1, call this Point A
    Label line segment GA "2 km" -- We're assuming this is horizontal distance, not line of sight. If it doesn't work out, we'll have to change this.
    Move South East (bearing 155 is between Due East = Bearing 90 and Due South = Bearing 180) and place the second field, Point B.
    Label line segment AB "3.5 km"

    There is a little drawing problem on this one. It's not clear where B is with relation to G. Is it East or West? It may not make any difference where we draw it, but it may be confusing at some point. Just keep it in mind.

    You should now be able to solve for the length of line segment BG. The Law of Sines gives the result.

    Do you yet see the solutions? It's mostly done.
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