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Thread: Given sin (B)=3 sin (2A+B), prove 2 tan A+tan(A+B)=0.

  1. May 24th 2011, 09:31 AM #1
    ayushdadhwal
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    Given sin (B)=3 sin (2A+B), prove 2 tan A+tan(A+B)=0.

    If sin (B)=3 sin (2A+B)
    Prove that 2 tan A+tan(A+B)=0
    Last edited by mr fantastic; May 24th 2011 at 01:41 PM. Reason: Re-titled.
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  2. May 24th 2011, 01:52 PM #2
    pickslides
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    A suggestion:

    Use \displaystyle \sin (A+B) = \sin A \cos B + \cos A \sin B on the right hand side.
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