I can't solve this :S
cosxsinx/tanx = 1 - sin^2x
thanks
Hi katiethegreat,
Maybe if you see it like this, it would help:
$\displaystyle \dfrac{\cos (x) \sin(x)}{\tan (x)}=$
$\displaystyle \dfrac{\cos(x) \sin(x)}{\frac{\sin (x)}{\cos (x)}}=$
$\displaystyle \dfrac{\cos (x) \sin (x)}{1} \cdot \frac{\cos (x)}{\sin (x)}=$
He just used the identity: $\displaystyle \tan (x) = \frac{\sin (x)}{\cos (x)}$
You should be able to finish now if you know $\displaystyle \sin^2(x)+\cos^2(x)=1$