I was wondering how I might go about solving sin (.77x)=-1/2

I know there would be two answers since it is a sine problem.

Thanks!

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- May 11th 2011, 11:40 AMmusic2283Solving for x in a trigonometric equation.
I was wondering how I might go about solving sin (.77x)=-1/2

I know there would be two answers since it is a sine problem.

Thanks! - May 11th 2011, 12:59 PMemakarov
Since sin(pi + pi/6) = -sin(pi/6) = -1/2 and sin(2pi - pi/6) = -sin(pi/6) = -1/2, one can see from the graph that the solutions to sin(y) = -1/2 are y = 7pi/6 + 2pi * k and 11pi/6 + 2pi * k for all integer k. Then the roots of the original equation can be found from .77x = y.

- May 11th 2011, 01:15 PMmusic2283
Thanks! That was a big help!