to solve use .Hi all,
The question I have is:
Calculate between 0 and 2.25s, the times at which the waveforms:
v=3cos3t and v=4sine6t cross.
So far I have calculated the time periods for both waveforms:
For Cosinewave: T = 2\pi /3 s
as v=3cos(3t) or v = 3cos(\omega t) where \omega = 2\pi f
Therefore: \omega = 2\pi /T = 3
So T = 2\pi /3
For Sinewave: T = 2\pi /6 s
as v=4sine(6t) or v = 4sine(\omega t) where \omega =2\pi f
Therefore: \omega = 2\pi /T = 6
So T = 2\pi /6
So it is evident that my sinewave is exactly twice the frequency of my Cosinewave, and
obviously what I want to achieve is to calculate the times where 3cos3t = 4sin6t.
I believe its required to use trigonometrical identoties to solve this problem from this point, but what approach/method to take I have no idea at this time.
Any help on this is greatly appriciated.
P.S: I am aware that I'm asking a question on my first post, but I intend to be of use to others here, where possible anyway!
did this help?