How do you turn these equations: 2 sin x sec x - 2 sqrt(3) sin x = 0 and
(2 cos x + sqrt(3)) sin x = 0 into quadratic equation format?
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How do you turn these equations: 2 sin x sec x - 2 sqrt(3) sin x = 0 and
(2 cos x + sqrt(3)) sin x = 0 into quadratic equation format?
Are you sure you want to put them into quadratic equation format? You can solve them by simply factoring.Quote:
Originally Posted by Devi09
You have a common factor of 2Sin(x) in the first equation:
2 Sin(x)(Sec(x) - sqrt(3))=0
Either Sin(x)=0
Or Sec(x)= Sqrt(3)
Etc... Can you clarify your question?
you have to solve each equation where 0 <= x <= 2pi. So the first one: sin x = 0 or sec = Sqrt(3). So find those in the unit circle and you got your answer?
as for the second one it's cos x = -Sqrt(3) / 2 or sin x = 0 and once again find those in the unit circle to get your answer I take it?
Yup.Quote:
Originally Posted by Devi09