For with , find the value of (do not evaluate ). Please show all steps to any working out. Any help will be appreciated!
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Originally Posted by Joker37 For with , find the value of (do not evaluate ). Please show all steps to any working out. Any help will be appreciated! Notice that
Originally Posted by Joker37 For with , find the value of (do not evaluate ). Please show all steps to any working out. Any help will be appreciated! , so , so we have: cos(x)=- x= x= if that , or
Last edited by ihavenonick; April 30th 2011 at 09:21 AM.
Originally Posted by ihavenonick sin(π/6)=\frac{1}{2}, so -sin(п/6)=\frac-{1}{2}, so we have: cos(x)=\frac-{1}{2} x=\pm acos(-1/2)+πn,n\in Z x=\pm 2π/3 +πn,n\in Z if that x=\frac-{3\pi}{2}, or x=\frac-{3\pi}{2} Besides doing the entire problem, you evaluated sin(π/6) - something that was expressly forbidden!
Originally Posted by TheChaz Notice that sure thing!
Originally Posted by TheChaz Besides doing the entire problem, you evaluated sin(π/6) - something that was expressly forbidden! I was editing the post at that moment. Look at this now.
Originally Posted by ihavenonick , so , so we have: cos(x)=- x= x= if that , or Actually the answer is meant to be but nevermind I think I understand how to do it now.
Originally Posted by ihavenonick , so , so we have: cos(x)=- x= x= if that , or I`m sorry I`ve done a mistake. Here is a correct answer: , so , so we have: cos(x)=- x= x= if that (or )
Jet another: cos(x)=- x= ; x= x= x= x= x= if that P.S. I don`t understand too. If calculate, the correct answer is as you wrote.