1. ## graph

graph of cos inverse(cosx)=y is

2. Some hints:

To find the inverse function what do you reflect y=cos(x) in?
and for the inverse to exist it must be 1 to 1.

3. Originally Posted by prasum
graph of cos inverse(cosx)=y is
You're meant to note that f(inverse f(x)) = x over the domain of inverse f(x).

4. from [o, pi] the graph would be y=x after that what should we do

5. Originally Posted by prasum
from [o, pi] the graph would be y=x after that what should we do
First of all, your domain is wrong.

Second, "after that", you go back and read what the question asked you to do.

6. Originally Posted by prasum
graph of cos inverse(cosx)=y is
This wording is ambiguous, depending on whether you denote the inverse cosine function as "cos inverse" or "inverse cos". I suspect that the OP and Mr F are interpreting it in opposite ways. So, starting from x, do you apply the cosine first, and then the inverse, or is it the other way round?

7. Originally Posted by Opalg
This wording is ambiguous, depending on whether you denote the inverse cosine function as "cos inverse" or "inverse cos". I suspect that the OP and Mr F are interpreting it in opposite ways. So, starting from x, do you apply the cosine first, and then the inverse, or is it the other way round?
its otherway round

8. Originally Posted by prasum
its otherway round
OK, then your domain is correct.