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  1. #1
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    graph

    graph of cos inverse(cosx)=y is
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  2. #2
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    Some hints:

    To find the inverse function what do you reflect y=cos(x) in?
    and for the inverse to exist it must be 1 to 1.
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  3. #3
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    Quote Originally Posted by prasum View Post
    graph of cos inverse(cosx)=y is
    You're meant to note that f(inverse f(x)) = x over the domain of inverse f(x).
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  4. #4
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    from [o, pi] the graph would be y=x after that what should we do
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  5. #5
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    Quote Originally Posted by prasum View Post
    from [o, pi] the graph would be y=x after that what should we do
    First of all, your domain is wrong.

    Second, "after that", you go back and read what the question asked you to do.
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  6. #6
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    Quote Originally Posted by prasum View Post
    graph of cos inverse(cosx)=y is
    This wording is ambiguous, depending on whether you denote the inverse cosine function as "cos inverse" or "inverse cos". I suspect that the OP and Mr F are interpreting it in opposite ways. So, starting from x, do you apply the cosine first, and then the inverse, or is it the other way round?
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  7. #7
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    Quote Originally Posted by Opalg View Post
    This wording is ambiguous, depending on whether you denote the inverse cosine function as "cos inverse" or "inverse cos". I suspect that the OP and Mr F are interpreting it in opposite ways. So, starting from x, do you apply the cosine first, and then the inverse, or is it the other way round?
    its otherway round
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  8. #8
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    Quote Originally Posted by prasum View Post
    its otherway round
    OK, then your domain is correct.
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