I have a right triangle with x, y, and z is the hypotenuse. It has angles A and B.The given information is that z=17, A=theta, and B=theta. I used the pythagorean theorem to deduce that the sides are equal length at sqrt(289/2). I am to find sin of theta which is the opposite side over the hypotenuse, and is sqrt(289/2)/17 which reduces to 1/sqrt(2) i am unsure how it goes from sqrt(289/2)/17 to 1/sqrt(2) could someone please explain?