hi,
i need to solve x^2-18x+53=0 to find length of hypotenuse. i am unsure how to do this so some help would be greatly appreciated!
would i do quadratic equation on it??
thanks
This
$\displaystyle x^2-18x+53=0$
is a quadratic equation. To solve it for x use the quadratic formula:
The quadratic equation $\displaystyle ax^2 + bx +c = 0$ has the solution:
$\displaystyle x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$
Plug in the values of a, b and c which you already know.