x + yi = cos(theta) + i sin(theta)
I understand this formula quite quite well...
But I have problem to think/understand how come if I have cos(theta) + i sin(theta) given I can come up with the x+yi form
Think in this way:
If someone gave me this input
cos(theta) + i sin(theta) == cos(0.6) + i sin(0.8) % in rad - and ask me to find x+yi version of this...
E.g. they look for x + yi , this is equal with 3 + 4i
How come I can come to this kind of conclusion? ...
NO NO NO ... I am asking how to get x=3 y=4 ? ... that what you say is quite easy, right?
Please read my first post, I think is quite well explained!
Based on maths we know this formula: x + yi = cos(theta) + i sin(theta)
Now think in this way, someone has given you the right-hand side e.g., cos(0.6) + i sin(0.8)
And is asking you to find the left-hand side, which in this case is 3 + 4i
But as you may guess, could be: 6 + 8i, 12 + 16i etc. as well
So my question is given the right-hand side can we find left-hand side? Since given left-hand side we can find right-hand side precisely!
Your got to be joking! Are you not?
Originally Posted by problady
Post an exact problem.
"Based on maths we know this formula: x + yi = cos(theta) + i sin(theta)" This is not correct, (trigonometrical form)
So and . (I hope you know that )
For your example: (which is wrong/ not complete)
1. False. cos(0.6) + i sin(0.8)=cos(theta) + i sin(theta) Try to guess what is wrong here! ^^
You have some serious problems with theory. Learn it! >.<
No I am not joking ... I am learning maths without a teacher thats right!
So, given this:
x + yi = cos(0.6) + i sin(0.8)
What is the value of x+yi - 3 + 4i, 6 + 8i or 12 + 16i - is possible to decide for one of those?
I had incomplete formula Plato sorry! This formula helps me to understand my way... no everything is clear!
Thanks to you Plato bot more to veileen