# Thread: Point that is perpendicular to a line of a plane?

1. ## Point that is perpendicular to a line of a plane?

I got this question below:

4. Find the equation of the plane passing through A(2, 1, -1), that is perpendicular to each line:

a) ((x-5)/1) = (y/3) = ((z-1)/-1)

How do I solve this equation?

I get close to the answer, but the D value is always off.

Never mind, I was miscalculating something. I got the correct answer. It is x+3y-z-6=0

2. Originally Posted by Barthayn
4. Find the equation of the plane passing through A(2, 1, -1), that is perpendicular to each line:
a) ((x-5)/1) = (y/3) = ((z-1)/-1)
Write the equation of a plane containing the point, A, with the direction vector of the line as the normal of the plane.

3. Yeah, I got the answer. You had to let a point be (x, y, z) and then take the vector of that with point A and then take the dot product of the vector with the directional vector. I made a miscalculate when I did it 3 times over :|