Proof number one:
prove that $\displaystyle \displaystyle \frac{cosx-sinx}{\cos2x} = \frac{cosx+sinx}{1+\sin2x}$
Proof number two:
prove that $\displaystyle \displaystyle \frac{1+tanx}{1-tanx} = \frac{\cos2x}{1-sinx}$
Any help is appreciated!
Proof number one:
prove that $\displaystyle \displaystyle \frac{cosx-sinx}{\cos2x} = \frac{cosx+sinx}{1+\sin2x}$
Proof number two:
prove that $\displaystyle \displaystyle \frac{1+tanx}{1-tanx} = \frac{\cos2x}{1-sinx}$
Any help is appreciated!