Trig Simplification

**rtblue** · March 28th 2011, 07:18 PM

Hey guys, I need to simplify this:
$\displaystyle \frac{sinx+cosx+1}{sinx+cosx-1}$

The correct answer is $\displaystyle cscxsecx+cscx+secx+1$

Can anyone give me any hints as to how to get from point A to point B?

Thanks in advance!

**TKHunny** · March 28th 2011, 08:20 PM

I am delighted at the very liberal usage of the word "simplify". It would be nice if it had a clear meaning. Anyway...

I'm tempted to "rationalize" the denominator.

$\frac{[\sin(x)+\cos(x)]+1}{[\sin(x)+\cos(x)]-1}\cdot\frac{[\sin(x)+\cos(x)]+1}{[\sin(x)+\cos(x)]+1}$

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