Is there a way to flip 1+SinX/CosX into CosX/1-SinX because i'm not finding it within my notes.
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No, but you can multiply the top and bottom of $\displaystyle \displaystyle \frac{\cos{x}}{1 - \sin{x}}$ by $\displaystyle \displaystyle 1 + \sin{x}$...
$\displaystyle \dfrac{1+\sin(x)}{\cos(x)} = \dfrac{1+\sin(x)}{\cos(x)} \times \dfrac{1-\sin(x)}{1-\sin(x)} =\dfrac{1-\sin^2(x)}{\cos(x)(1-\sin(x))}= ... $
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