# SinX TanX how can i combine these to get a form of (SinX)^2

Remember that $\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}} = \pm\frac{\sin{x}}{\sqrt{1 - \sin^2{x}}}$.
So $\displaystyle \sin{x}\tan{x} = \pm\frac{\sin^2{x}}{\sqrt{1 - \sin^2{x}}}$.