Here are some more problems that need checking from my other thread I made.
1)
2)
)
For this problem, does it matter if the right side's answer is the same value on the left side but flipped?
3)
Doing the right side:
Here are some more problems that need checking from my other thread I made.
1)
2)
)
For this problem, does it matter if the right side's answer is the same value on the left side but flipped?
3)
Doing the right side:
My objective is to find the other side.
I also want to know if my method for this problem is legal:
Cross multipling ( sin x / cos x) * (cos x / sin x) would give me one.
Here i canceled the ones out and got ' cot ^ 2 x + tan ^ 2 x '.
Canceling the ones again would give me csc^ 2 x + sec^2x.
Edit: I misunderstood your approach, I think it works, other than the fact that you cancel the ones at the end. When you reach the stage , you can just use identities to show that it is the same as . I'll leave my method here, but after rereading, I think your proof is otherwise fine.
Generally, you'd start with the side which is easiest to simplify. Here, that's the right hand side. Start by putting everything over a common denominator:
which is the left hand side.
You also haven't finished 2) - you can simplify the fraction further using the identity
Okay that helped me a little bit, I also have another question unrelated to this topic but with dealing with Solving Right triangles. When going about solving the outer sides, how do I know whether or not I should take the given outside side and times it by whatever degree given inside the triangle, as opposed to dividing the outside side by the inside? (Example