I am just trying to get some help on how to get this equation right. I have it equal to 0. Anything will help thanks. sin5x-sinx=2cos3x sin4x-2cos3x=0 (I think this is correct, just need help moving on to the next step.
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Originally Posted by PintsofGuinness sin5x-sinx=2cos3x sin4x-2cos3x=0 What?. $\displaystyle \sin A-\sin B=2\cos\dfrac{A+B}{2}\sin \dfrac{A-B}{2}$ So, $\displaystyle \sin 5x-\sin x=2\cos 3x \sin 2x$
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