hi, I know that you need to sub in a trig identity to the equation... but I don't know which one or what to do... I'm so confused. sin(2theta) + 4cos(theta) = 0
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Originally Posted by [nuthing] hi, I know that you need to sub in a trig identity to the equation... but I don't know which one or what to do... I'm so confused. sin(2theta) + 4cos(theta) = 0 use the double angle identity, $\displaystyle \sin(2t) = 2\sin{t}\cos{t}$, factor and solve.
Originally Posted by skeeter use the double angle identity, $\displaystyle \sin(2t) = 2\sin{t}\cos{t}$, factor and solve. yeah, but how?
Originally Posted by [nuthing] yeah, but how? Well can you factor $\displaystyle 2xy-4y~?$
Originally Posted by [nuthing] yeah, but how? 1. Use the double angle formula 2. Factor 3. Solve 1. sin(2t) + 4cos(t) = 0 becomes 2sin(t)cos(t) + 4cos(t) = 0 2. Take out the greatest common factor 3. Set each factor equal to zero, using the "zero product property" (field)
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