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A plane heads on a bearing of 210 degrees at 500 mph; the winds at the cruising altitude are 75 mph from the southwest to the northeast.
Write the vector u representing the velocity of the plane relative to the air and the vector v representing the velocity of the wind.
Can someone please help and explain this to me?
If I worked this out correctly, I think vector u = <-250√3,-250>
and vector v = <-75,0>.
Is this right?
this really is not a good venue for teaching ... hopefully you have been taught the basics.Quote:
Originally Posted by Sky
start by making a sketch ... note that the directions are more than likely referenced to true north.
Air vector + Wind vector = Ground vector
you can manipulate vectors using the law of sines/cosines or by using components.
Here is my sketch:
http://i11.photobucket.com/albums/a1...e/Airplane.jpg
Upon further evalution, this seems to be incorrect. Ugh.
3 digit bearings are usually measured clockwise from true north ... otherwise, the problem usually uses the 30 degrees west of south type of description.
Whoops.
Here we go?
http://i11.photobucket.com/albums/a1...Airplane-1.png
ok ... u and v = ???
u = <-250,-250√3>
v = <-75,0>
?
And the ground vector = <-325,-250√3> ?
vector v (the wind vector) blowing NE at 75 mph ...
$\displaystyle \vec{v} = \left<\dfrac{75\sqrt{2}}{2},\dfrac{75\sqrt{2}}{2}\ right>$
Ah. Okay.
So, in turn, the ground vector would equal <-197,-380> ?
come on ... you can add components as easily as I can.Quote:
Originally Posted by Sky
I'll take that as a yes.Quote:
Originally Posted by skeeter
Thanks
