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**Sleight** Okay, this one I don't even know how to start. I really have given this a go for a few days now, but I just am not grasping something. I think my memory has failed me with logarithms.

$\displaystyle 4\cdot16^{sin^2(x)}=64^{sin(x)}$

I know 4(16)=64, but that shouldn't fit with this problem. It seems to be more of a distraction. I know that $\displaystyle \log_bx=y$ is the same as $\displaystyle b^y=x$, but I can't quite think of what to do since we have exponents on both sides of the equation.

Any help on getting started would be appreciated.