Originally Posted by

**masters** Should be a simple solution....but....it's eluding me.

A batter hits a ball with an initial velocity of $\displaystyle v_0$ of $\displaystyle 100 \text{ f/s }$ at an angle $\displaystyle \theta$ to the horizontal.

An outfielder catches the ball $\displaystyle 200 \text{ feet }$ from home plate.

Find $\displaystyle \theta$ if the range of a projectile is given by the formula:

$\displaystyle R=\frac{1}{32}v_0^2 \sin 2 \theta$

Here's what I've done so far.

$\displaystyle 200=\frac{1}{32}(100)^2 \sin 2 \theta$

$\displaystyle 6400=10000 \sin 2 \theta$

$\displaystyle \frac{16}{25}=\sin 2\theta$