Hi all...I have some homework that I'm having some problems with.
Here is the word problem that I'm confused about...
A ship travels 18.5 km on a course of 31.2° south of east, then 12.7 km due south, then 21.5 km on the course of 61.3° west of south, where it lands. Find the displacement and the angle traveled from the starting point to the landing point.
Here is what I did to try and solve it...
18.5cos31.2 + 12.7cos58.8 + 21.5cos61.3 = 32.73
18.5sin31.2 + 12.7sin58.8 + 21.5sin61.3 = 39.3
32.73^2 + 39.3^2 * 1/2 = 51.15
tan^-1(39.3 / 32.73) = 50.22°
so...51.15 at 50.22° is my answer.
For some reason, this just does not look right. Can anyone check my logic, and straighten me out here?