2tanē X + 2secē X - secX = 12 can anyone help with this in laymans terms maths isnt my number one cheers
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Originally Posted by mwin002 2tanē X + 2secē X - secX = 12 can anyone help with this in laymans terms maths isnt my number one cheers Well $\displaystyle \displaystyle \tan^2 x = \sec^2x-1$ Therfore $\displaystyle \displaystyle 2\tan^2 x + 2 \sec^2 x - \sec x = 12$ becomes $\displaystyle \displaystyle 2( \sec^2x-1) + 2 \sec^2 x - \sec x = 12$ Now you have everything in terms of $\displaystyle \sec x$
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